11.Thermodynamics
medium

In an adiabatic process where in pressure is increased by $\frac{2}{3}\% $ if $\frac{{{C_p}}}{{{C_v}}} = \frac{3}{2},$ then the volume decreases by about

A

$\frac{4}{9}\% $

B

$\frac{2}{3}\% $

C

$4\%$

D

$\frac{9}{4}\% $

Solution

$\frac{\Delta \mathrm{P}}{\mathrm{P}}=-\gamma \frac{\Delta \mathrm{V}}{\mathrm{V}} \quad \frac{2}{3} \times \frac{1}{\gamma}=\frac{\Delta \mathrm{V}}{\mathrm{V}} \quad \frac{\Delta \mathrm{V}}{\mathrm{V}}=-\frac{4}{9} \%$

Standard 11
Physics

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